**Question 1. A Movie Is Scheduled For Two Hours. The Theatre Advertisements Are 3.8 Minutes Long. There Are Two Previews; One Is 4.6 Minutes Long, And The Other Is.2.9 Minutes Long. The Rest Of Time Is Devoted To The Feature Film. How Long Is The Feature Film?****Answer :**Total time apart from the feature film = { 3.8 + 4.6 + 2.9 }=11.3 minutes,

therefore time for feature film = { 120-11.3}min= 108.7 min.

**Question 2. Bhajan Singh Purchased 120 Reams Of Paper At Rs. 80 Per Ream. He Spent Rs. 280 On Transportation. Paid Octrai At The Rate Of 40 Paise Per Ream And Paid Rs. 72 To The Coolie. If He Wants To Have A Gain Of 8 %. What Must Be The Selling Price Per Ream?****Answer :**C.P of 120 reams = Rs. (120 × 80 + 280 + 72 + 120 × 40) = Rs. 10000

C.P of 1 ream = (10000/120) = Rs. (250/3)

S.P of 1 ream = Rs. (108/100 × 250/3) = Rs. 90

**Question 3. In A Race Of 200 M, A Can Beat B By 31 M And C By 18 M. In A Race Of 350 M, C Will Beat B By?****Answer :**It means, when A convers 200 m, B covers only (200-31)=169 m

and C covers only (200-18)=182 m

=> When C covers 182 m, B covers 169 m

=> When C covers 350 m, B covers 169182×350 = 325 m

Hence, C beats B by 350-325 = 25 metre

**Question 4. Three Persons A, B And C Divide A Certain Amount Of Money Such That A’s Share Is Rs. 4 Less Than Half Of The Total Amount, B’s Share Is Rs. 8 More Than Half Of What Is Left And Finally C Takes The Rest Which Is Rs. 14. Find The Total Amount They Initially Had With Them?****Answer :**Let the total amount be Rs. p.

Let shares of A and B be Rs. x and Rs. y respectively.

C’s share was Rs. 14

we have, x + y + 14 = p —– (1)

From the given data, x = (p/2) – 4 —– (2)

Remaining amount = p – (p/2 – 4) => p/2 + 4.

y = 1/2(p/2 + 4) + 8 => p/4 + 10 —– (3)

From (1), (2) and (3)

p/2 – 4 + p/4 + 10 + 14 = p

3p/4 + 20 = p

p/4 = 20 => p = Rs. 80.

**Question 5. 105.126 * 35.201 – 90.23 * 3 + 55.11 * 27.01 = ?****Answer :**105.126 * 35.201 – 90.23 * 3 + 55.11 * 27.01

= 105 * 35 – 90 * 3 +55 * 27 = 3675 – 270 + 1485

= 5160 – 270 = 4890

**Question 6. A Is 30% More Efficient Than B. How Much Time Will They, Working Together, Take To Complete A Job Which A Alone Could Have Done In 23 Days?****Answer :**Ratio of times taken by A and B = 100:130 = 10:13

Suppose B takes x days to do the work.

x = (23 * 13)/10 = 299/10

A’s 1 day work = 1/23; B’s 1 day work = 10/299

(A + B)’s 1 day work = (1/23 + 10/299) = 1/13

A and B together can complete the job in 13 days.

**Question 7. If The Length, Breadth And The Height Of A Cuboid Are In The Ratio 6: 5: 4 And If The Total Surface Area Is 33300 Cm2, Then Length Breadth And Height In Cms, Are Respectively?****Answer :**Length = 6x

Breadth = 5x

Height = 4x in cm

Therefore, 2(6x × 5x + 5x × 4x + 6x × 4x) = 33300

148×2 = 33300

=> x2 = 33300/148 = 225

=> x = 15.

Therefore, Length = 90cm,

Breadth = 75cm,

Height = 60cm

**Question 8. There Are Two Examinations Rooms A And B. If 10 Students Are Sent From A To B, Then The Number Of Students In Each Room Is The Same. If 20 Candidates Are Sent From B To A, Then The Number Of Students In A Is Double The Number Of Students In B. The Number Of Students In Room A Is?****Answer :**Let the number of students in rooms A and B be x and y respectively.

Then, x – 10 = y + 10 x – y = 20 …. (i)

and x + 20 = 2(y – 20) x – 2y = -60 …. (ii)

Solving (i) and (ii) we get: x = 100 , y = 80.

The required answer A = 100.

**Question 9. A Person Bought An Article And Sold It At A Loss Of 10%. If He Had Bought It For 20% Less And Sold It For Rs. 55 More. He Would Have Had A Profit Of 40%. The C.p. Of The Article Is ?****Answer :**Let C.P. = Rs. P

Then S.P. = Rs. (90/100) x P = Rs. (9 x P)/10

New C.P. = Rs. (80/100) x P = Rs. (4 x P)/5

Now, Gain = 40%

∴ New S.P. Rs. (140/100 x 4P/5) = Rs. 28P/25

∵ 28P/25 – 9P/10 = Rs. 250

**Question 10. The Weights Of Three Boys Are In The Ratio 4 : 5 : 6. If The Sum Of The Weights Of The Heaviest And The Lightest Boy Is 45 Kg More Than The Weight Of The Third Boy, What Is The Weight Of The Lightest Boy?****Answer :**Let the weights of the three boys be 4k, 5k and 6k respectively.

4k + 6k = 5k + 45

=> 5k = 45 => k = 9

Therefore the weight of the lightest boy

= 4k = 4(9) = 36 kg.

**Question 11. What Is The Least Number To Be Subtracted From 11, 15, 21 And 30 Each So That Resultant Numbers Become Proportional?****Answer :**Let the least number to be subtracted be x, then 11 – x, 15 – x, 21 – x and 30 – x are in proportion.

<=> (11 – x) : (15 – x) = (21 – x) : (30 – x)

=> (11 – x)(30 – x) = (15 – x)(21 – x)

From the options, when x = 3

=> 8 * 27 = 12 * 18

**Question 12. Two Men Amar And Bhuvan Have The Ratio Of Their Monthly Incomes As 6 : 5. The Ratio Of Their Monthly Expenditures Is 3 : 2. If Bhuvan Saves One-fourth Of His Income, Find The Ratio Of Their Monthly Savings?****Answer :**Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.

Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.

Savings of Bhuvan every month = 1/4(5x)

= (His income) – (His expenditure) = 5x – 2y.

=> 5x = 20x – 8y => y = 15x/8.

Ratio of savings of Amar and Bhuvan

= 6x – 3y : 1/4(5x) = 6x – 3(15x/8) : 5x/4 = 3x/8 : 5x/4

= 3 : 10.

**Question 13. On A Particular Morning The Temperature Went Up 1 ° Every Two Hours. If The Temperature Was 53° At 5 A.m., At What Time Was It 57°?****Answer :**Difference in temperature= {57-53}= 4 degrees.

1 degrees rise happens in 2 hours ,

so 4 degrees rise would happen in 4 x 2 = 8 hrs,

so it will be 8 hrs after 5 A.M. i.e. 1 P.M.

**Question 14. A Bottle Is Sold At A Loss Of 9%. Had It Sold For Rs. 15 More, A Profit Of 25/2% Would Have Gained. What Is The Cost Price Of The Bottle (approx)?****Answer :**Let the cost price of the bottle = Rs. 100

Selling price of the bottle = Rs. 100 – Rs. 9 = Rs. 91

Then, from the given data,

=> 112 (1/2) – 91 = 15

=> 21 (1/2) = 15

=> 43 = 15

Then 100 = ?

1500/43 = 34.885 =~ 35

Hence, the cost price of the bottle = Rs. 35

**Question 15. Buy At 30 Cell At 50. What Is The Profit Percentage?****Answer :**Cost price = Rs. 30

Selling price = Rs. 50

Gain = Rs. 20

Profit % = Gain/cost price x 100 = 20/50 x 100 = 40%

**Question 16. The Cost Price Of A College Bag Is 240% More Than The Profit Obtained On It Selling At Rs. 1540. What Is The Cost Price Of That College Bag?****Answer :**Let the profit be Rs. p

Then Cost price of the bag = 340p/100 = 3.4p

According to question,

3.4p + p = 1540

4.4p = 1540

p = 1540/4.4

p = 350

The profit p = Rs, 350

Hence, The cost price of the bag = 3.4p = 3.4 x 350 = Rs. 1190.

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