## Ericsson Aptitude Interview Questions & Answers

1. Question 1. A Man Completes 30km Of A Journey At 6km/hr And The Remaining 40km Of The Journey In 5 Hours. His Average Speed For The Whole Journey Is

Total distance = (30 + 40)km = 70km

Total time taken = (30/6 + 5)hrs = 10hrs

Average speed = 70/10km/hr = 7km/hr

2. Question 2. Rekha Bought A Saree For Rs.1240 And Sold It For Rs. 1147. Find Her Loss And Loss Percent. ?

C.P of saree = Rs. 1240

S.P of saree = Rs. 1147

Loss = CP-SP

= Rs (1240-1147)

= Rs. 93

Loss% = 931240×100

= 7.5 %

3. Aptitude Interview Questions

4. Question 3. A Boy Buys 9 Apples For Rs. 9.60 And Sells Them At 11 For Rs.12. Find His Gain Or Loss Percent ?

C.P of 9 apples = Rs. 9.60

CP of 1 apple = 9.609=1.06

S.P of 11 apple = Rs. 12

SP of 1 apple = 1211=1.09

Clearly,

SP of 1 apple > CP of 1 apple

We get profit on selling apples = SP-CP

= 0.022

Gain% = 0.0221.06×100

= 2.27 %

5. Question 4. A Train 100 Meters Long Completely Crosses A 300 Meters Long Bridge In 45 Seconds. What Is The Speed Of The Train Is?

S = (100 + 300)/45 = 400/45 * 18/5 = 32

6. Question 5. A Retailer Buys A Radio For Rs.225. His Overhead Expense Are Rs15. If He Sells The Radio For Rs.300, Determine The Profit Percentage.

Total expenses = Rs.(225+15) = Rs.240

S.P = Rs.300

Profit = SP-CP = Rs (300-240) = Rs.60

Profit% = 60240×100

= 25%

7. Ericsson JAVA Interview Questions

8. Question 6. A Retailer Buys A Cooler For Rs.1200 And Overhead Expenses Are On It Are Rs.40. If He Sells The Cooler For Rs.1550, Determine The Profit Percentage.?

Cooler cost = Rs.1200

Total cost = Rs.(1200+40) = Rs.1240

S.P of the cooler = 1550

Profit = S.P-C.P

= Rs.(1550-1240)

= Rs. 310

Profit% = 3101240×100

= 25%

9. Question 7. A Dealer Buys A Wrist Watch For Rs. 225 And Spends Rs.15 On Its Repairs. If He Sells The Same For Rs.300, Find His Profit Percentage ?

A dealer buys a wrist watch for Rs.225

Money spent on repairing the watch = Rs.15

Total expenses = Rs.(225+15) = Rs.240

S.P = Rs.300

Profit = SP-CP = Rs (300-240) = Rs.60

Profit% = 60240×100

= 25%

10. HR Interview Questions

11. Question 8. Ramesh Bought Two Boxes For Rs.1300. He Sold One Box At A Profit Of 20% And The Other At A Loss Of 12%. If The Selling Price Of Both Boxes

Let the cost price of the first box be Rs. x

Therefore, the cost of the second box will be Rs.(1300-x)

Profit on the first box = 20%

Loss on the second box = 12%

S.P of the first box = 120×100

= 6×5

S.P of the second box = Rs. 28600 – 88×100

= Rs.28600 – 22×25

Selling prices of both of the boxes are equal. So,

= 6×5 = Rs.28600 – 22×25

= x = 14300 – 110×260

= x= 550

The cost price of first box is Rs. 550

Cost price of the second box = Rs.(1300-550)

= Rs. 750

The cost prices of the 2 boxes are Rs.550 and Rs.750 respectively.

12. Question 9. If The Selling Price Of 10 Pens Is Equal To Cost Price Of 14 Pens, Find The Gain Percent ?

Let the cost price of one pen be Rs. C

The selling price be Rs. S

Therefore, 10S = 14C

C = 1014S

However, the cost price is less than the selling price.

Profit = 140-100

Profit % = 40%

The required profit percentage is 40%.

13. Java 9 Interview Questions

14. Question 10. If The Cost Price Of 18 Chairs Be Equal To Selling Price Of 16 Chairs, Find The Gain Or Loss Percent

Let the cost price of one chair be Rs. C

Selling price be Rs. S

Therefore, 18C = 16S

However, the cost price of the chair is more than that of selling price.

Profit% = 1800−160018

= 20016

= 12.5%

The required profit percent is 12.5%

15. Question 11. A Car Covers A Distance Of 624 Km In 6 ½ Hours. Find Its Speed ?

624/6 = 104 kmph

16. Zensar Technologies Aptitude Interview Questions

17. Question 12. Ravish Sold His Motorcycle To Vineet At A Loss Of 28%. Vineet Spent Rs.1680 On It’s Repairs And Sold The Motorcycle To Rahul For Rs.35910, Thereby Making Profit Of 12.5%, Find The Cost Price Of The Motorcycle For Ravish.

Let the cost price of the motor cycle for Ravish be Rs. x

Loss % = 28%

S.P = 72×100

Selling price of the motorcycle for ravish = cost price of the motorcycle for vineet

Money spent on repairs = Rs.1680

Therefore, total cost price of the motorcycle for vineet =

Rs(72×100 + 1680(12.5) + 100(100)

= (35910)(100)(100) = 72×100

= 35910000 = 8100x +18900000

= x= 42000

Ravish bought the motorcycle for Rs.42000

18. Aptitude Interview Questions

19. Question 13. By Selling A Book For Rs.258, A Bookseller Gains 20%. Find How Much Should He Sell To Gain 30% ?

Selling price of the book = Rs. 258

Gain = 20%

S.P = 120100×258

= Rs. 215

C.P = 130100×215

= Rs. 279.50

Therefore, the book seller must sell the book at Rs. 279.50 to make 30% profit.

20. Question 14. A Defective Briefcase Costing Rs.800 Is Being Sold At A Loss Of 8%. If The Price Is Further Reduced By 5%, Find Its Selling Price ?

C.P of the briefcase = Rs. 800

Loss = 8%

S.P = 92100×800

= Rs. 736

The price is decreased further by 5 %

S.P = 95100×736

= Rs. 699.20

The selling price of the briefcase is Rs. 699.20

21. Question 15. By Selling 90 Ball Pens For Rs160 A Person Loses 20%. How Many Ball Pens Should Be Sold At Rs.96 So As To Have A Profit Of 20% ?

S.P of 90 ball pens = Rs 160

Loss= 20%

C.P = 10020×160

= Rs. 200

Now,

S.P of 90 ball pens = Rs. 96

Profit = 20%

C.P = 100120×96

= Rs .80

Rs .200 is the cost price of 90 ball pens.

Therefore, Rs.80 is the C.P of = 90 (80200) =  36 ball pens

Thus, 36 ball pens should be sold at Rs. 96 to earn  a profit of 20%

22. Infosys Aptitude Interview Questions

23. Question 16. A Man Sells An Article At A Profit Of 25%. If He Had Bought It At A 20% Less And Sold It For Rs.36.75 Less, He Would Have Gained 30%. Find The Cost Price Of The Article ?

Let the C.P be the article be Rs. x

Profit = 25%

Original S.P = x + 25100x

= Rs. 5×4

If he purchased it at 20% less,

C.P = x- 20100x

= Rs. 4×5

He sold the article at Rs. 36.75

So, the selling price = Rs. 5×4 – 36.75

Given, that he would have gained 30% selling at that price.

Therefore, gain% = S.P-C.P

= 5×4 -36.75 – 4×5

= 25x−16×20 -36.75

So, gain % = 9×20-36.75- 4×5(100)

= 18375x = 18375105

= x = 175

The cost price of the article is Rs. 175.

24. Question 17. If A Train, Travelling At A Speed Of 90 Kmph, Crosses A Pole In 5 Sec, Then The Length Of Train Is?

D = 90 * 5/18 * 5 = 125 m

25. IBM Aptitude Interview Questions

26. Question 18. A Dealer Bought Two Tables For Rs.3120. He Sold One Of Them At A Loss Of 15% And The Other At A Gain Of 36%. . Then, He Found That Each Table Was Sold For The Same Price. Find The Cost Price Of Each Table.

Given that the selling price is same for both the tables.

Let the C.P of 1 table be x

Then the C.P of the other table be = Rs.3120-x

Loss on the first table = 15%

Therefore, S.P = 85×10

= 0.85x

Gain on the second table = 36%

136(3120-x)

Since both the tables have the same S.P

2.21x = 4243.20

= x= 1920

The cost price of the table is Rs.1920

The cost price of the other table is Rs.(3120-1920) = Rs.1200

27. Ericsson JAVA Interview Questions

28. Question 19. Mariam Bought Two Fans Rs.3605. She Sold One Of Them At A Profit Of 15% And The Other One At A Loss Of 9 %. If Mariam Obtained The Same Amount For Each Fan, Find The Cost Price Of The Each Of The Fans.

It is given that the S.P is same for both of the fans.

Let the C.P of the first fan be Rs. x

Therefore, C.P of the second fan be Rs. (3605-x)

Profit on the first fan = 15%

Loss on the second fan = 6%

For the first fan, S.P = 115×100

= 23×20

For the second fan, S.P = 91×100

Since, S.P of both the fans is the same

= 23×20 = 3605 – 91×100

= x = 1592

C.P of the first fan = Rs. 1592

C.P of the second fan = Rs.(3605-1592)

= Rs. 2012.50

The cost prices of the both of the fans are Rs.1592 and Rs. 2012.50 respectively.

29. Question 20. Some Toffees Are Bought At A Rate Of 11 For Rs.10 And The Same Number At The Rate Of 9 For Rs.10. If The Whole Lot Is Sold At One Per Toffee, Find The Gain Or Loss Percent On The Whole Transaction.

Let the total number of toffees bought be Rs. x

Let x2  at the rate of 11 are bought for Rs.10,

Total money spent on toffees = 200×198

= 100×99

It is given that x toffees are sold at Re.1 per toffee.

Therefore, the selling price of x toffees = Rs. x(1)

As C.P is more than S.P, it will be the loss.

Loss= C.P-S.P

= 100×99 – x

= x99

Loss% = 1%

The total loss on the whole transaction would be 1%

30. Capgemini Aptitude Interview Questions

31. Question 21. A Tricycle Is Sold At A Gain Of 16%. Had It Been Sold For Rs.100 More, The Gain Would Have Been 20%. Find The C.p Of The Tricycle ?

Let the S.P of the tricycle be Rs. x

Let the C.P of the tricycle be Rs. y

Gain % = 16%

Then we have,

= x= y+ 16y100

= x = y+ 0.16y

When S.P increases by Rs.100, we get

= x+ 100 = y + 20 y 100

Putting x = 1.6y

= 1.16y+100 = y+0.2y

= 1.16y +100 = 1.2y

= y = 2500

The C.P of the cycle is 2500

Thus, C.P of the tricycle is Rs. 2500.

32. Question 22. Shabana Bought 16 Dozens Ball Pens And Sold Them At A Loss Of To S.p Of 8 Ball Pens. Find:

(i) Her Loss Percent

(ii) P Of 1 Dozen Ball Pens, If She Purchased These 16 Dozens Ball Pens For Rs.576

(i) Number of pens bought = 16(12) = 192

Let S.P of one pen be Rs. x

Therefore, S.P of 192 pens = 192x

C.P of 8 pens = Rs. 8x

It is given that S.P of 8 pens is equal to the loss on selling 192 pens.

Therefore, loss= Rs.8x

C.P of 192 pens = Rs 576

Loss = C.P –S.P

= 8x = 576 – 192×200

= 576 x = 576200

=x= 2.88

Therefore, loss= RS.23.04

Loss% = 4%

(ii) P of 1 pen = Rs.2.88

Therefore, S.P of 1 dozen pens = 12x = 12(2.88)

= Rs.34.56

33. Question 23. The Difference Between Two Selling Pieces Of A Shirt At A Profit Of 4 % And 5% Is Rs.6. Find:

(i) P Of The Shirt

(ii) The Two Selling Prices Of The Shirt

Let the C.P of both the shirt be RS. X

For 1 shirt profit = 4%

Profit% = Rs. 0.04x

S.P = Rs.1.04x

For 2 shirt profit = 5%

Profit% = Rs. 0.05x

S.P = Rs.1.05x

It is given that the difference between their profits is Rs.6

So, 1.05x-1.04x = 6

= x = Rs.600

Thus, C.P = Rs.600

S.P of 1 shirt 1 = Rs.1.04x = Rs. 1.04(600)= Rs. 624

S.P of 1 shirt 2 = Rs.1.05x = Rs. 1.05(600)= Rs. 630

34. Cognizant Aptitude Interview Questions

35. Question 24. Toshiba Bought 100 Hens For Rs.8000 And Sold 20 Of These At A Gain Of 5%. At What Gain Percent She Must Sell The Remaining Hens So As To Gain 20% On The Whole ?

C.P of 100 hens = RS. 8000

Cost of one hen = 8000100

Rs. 80 C.P of 20 hens = Rs (80*20) = Rs. 1600

Gain = 5%

S.P = 105100×1600

= Rs. 1680

C.P of 80hens = Rs.(80*80) = Rs. 6400

Gain on 80 hens – C.P 80 hens

Gain on 100 hens = gain on 80 hens + gain on 20 hens

= 80+ S.P of 80 hens – 6400

S.P of 80 hens = Rs (1600+6400-80)

S.P of 80 hens = Rs. 7920

Gain on 80 hens = S.P of 80 hens – C.P of 80 hens

= Rs. (792-6400) = Rs. 1520

Gain % 80 hens = 15206400×100

= 23.75%

Therefore, Toshiba gained 23.75% on 80 hens.

36. HR Interview Questions