Question 1. A Man Completes 30km Of A Journey At 6km/hr And The Remaining 40km Of The Journey In 5 Hours. His Average Speed For The Whole Journey Is
Answer :
Total distance = (30 + 40)km = 70km
Total time taken = (30/6 + 5)hrs = 10hrs
Average speed = 70/10km/hr = 7km/hr
Question 2. Rekha Bought A Saree For Rs.1240 And Sold It For Rs. 1147. Find Her Loss And Loss Percent. ?
Answer :
C.P of saree = Rs. 1240
S.P of saree = Rs. 1147
Loss = CP-SP
= Rs (1240-1147)
= Rs. 93
Loss% = 931240×100
= 7.5 %
Question 3. A Boy Buys 9 Apples For Rs. 9.60 And Sells Them At 11 For Rs.12. Find His Gain Or Loss Percent ?
Answer :
C.P of 9 apples = Rs. 9.60
CP of 1 apple = 9.609=1.06
S.P of 11 apple = Rs. 12
SP of 1 apple = 1211=1.09
Clearly,
SP of 1 apple > CP of 1 apple
We get profit on selling apples = SP-CP
= 0.022
Gain% = 0.0221.06×100
= 2.27 %
Question 4. A Train 100 Meters Long Completely Crosses A 300 Meters Long Bridge In 45 Seconds. What Is The Speed Of The Train Is?
Answer :
S = (100 + 300)/45 = 400/45 * 18/5 = 32
Question 5. A Retailer Buys A Radio For Rs.225. His Overhead Expense Are Rs15. If He Sells The Radio For Rs.300, Determine The Profit Percentage.
Answer :
Radio cost = Rs 225
Overhead expenses = Rs 15
Total expenses = Rs.(225+15) = Rs.240
S.P = Rs.300
Profit = SP-CP = Rs (300-240) = Rs.60
Profit% = 60240×100
= 25%
Question 6. A Retailer Buys A Cooler For Rs.1200 And Overhead Expenses Are On It Are Rs.40. If He Sells The Cooler For Rs.1550, Determine The Profit Percentage.?
Answer :
Cooler cost = Rs.1200
Overhead cost = Rs.40
Total cost = Rs.(1200+40) = Rs.1240
S.P of the cooler = 1550
Profit = S.P-C.P
= Rs.(1550-1240)
= Rs. 310
Profit% = 3101240×100
= 25%
Question 7. A Dealer Buys A Wrist Watch For Rs. 225 And Spends Rs.15 On Its Repairs. If He Sells The Same For Rs.300, Find His Profit Percentage ?
Answer :
A dealer buys a wrist watch for Rs.225
Money spent on repairing the watch = Rs.15
Total expenses = Rs.(225+15) = Rs.240
S.P = Rs.300
Profit = SP-CP = Rs (300-240) = Rs.60
Profit% = 60240×100
= 25%
Question 8. Ramesh Bought Two Boxes For Rs.1300. He Sold One Box At A Profit Of 20% And The Other At A Loss Of 12%. If The Selling Price Of Both Boxes
Answer :
Let the cost price of the first box be Rs. x
Therefore, the cost of the second box will be Rs.(1300-x)
Profit on the first box = 20%
Loss on the second box = 12%
S.P of the first box = 120×100
= 6×5
S.P of the second box = Rs. 28600 – 88×100
= Rs.28600 – 22×25
Selling prices of both of the boxes are equal. So,
= 6×5 = Rs.28600 – 22×25
= x = 14300 – 110×260
= x= 550
The cost price of first box is Rs. 550
Cost price of the second box = Rs.(1300-550)
= Rs. 750
The cost prices of the 2 boxes are Rs.550 and Rs.750 respectively.
Question 9. If The Selling Price Of 10 Pens Is Equal To Cost Price Of 14 Pens, Find The Gain Percent ?
Answer :
Let the cost price of one pen be Rs. C
The selling price be Rs. S
Therefore, 10S = 14C
C = 1014S
However, the cost price is less than the selling price.
Profit = 140-100
Profit % = 40%
The required profit percentage is 40%.
Question 10. If The Cost Price Of 18 Chairs Be Equal To Selling Price Of 16 Chairs, Find The Gain Or Loss Percent
Answer :
Let the cost price of one chair be Rs. C
Selling price be Rs. S
Therefore, 18C = 16S
However, the cost price of the chair is more than that of selling price.
Profit% = 1800−160018
= 20016
= 12.5%
The required profit percent is 12.5%
Question 11. A Car Covers A Distance Of 624 Km In 6 ½ Hours. Find Its Speed ?
Answer :
624/6 = 104 kmph
Question 12. Ravish Sold His Motorcycle To Vineet At A Loss Of 28%. Vineet Spent Rs.1680 On It’s Repairs And Sold The Motorcycle To Rahul For Rs.35910, Thereby Making Profit Of 12.5%, Find The Cost Price Of The Motorcycle For Ravish.
Answer :
Let the cost price of the motor cycle for Ravish be Rs. x
Loss % = 28%
S.P = 72×100
Selling price of the motorcycle for ravish = cost price of the motorcycle for vineet
Money spent on repairs = Rs.1680
Therefore, total cost price of the motorcycle for vineet =
Rs(72×100 + 1680(12.5) + 100(100)
= (35910)(100)(100) = 72×100
= 35910000 = 8100x +18900000
= x= 42000
Ravish bought the motorcycle for Rs.42000
Question 13. By Selling A Book For Rs.258, A Bookseller Gains 20%. Find How Much Should He Sell To Gain 30% ?
Answer :
Selling price of the book = Rs. 258
Gain = 20%
S.P = 120100×258
= Rs. 215
C.P = 130100×215
= Rs. 279.50
Therefore, the book seller must sell the book at Rs. 279.50 to make 30% profit.
Question 14. A Defective Briefcase Costing Rs.800 Is Being Sold At A Loss Of 8%. If The Price Is Further Reduced By 5%, Find Its Selling Price ?
Answer :
C.P of the briefcase = Rs. 800
Loss = 8%
S.P = 92100×800
= Rs. 736
The price is decreased further by 5 %
S.P = 95100×736
= Rs. 699.20
The selling price of the briefcase is Rs. 699.20
Question 15. By Selling 90 Ball Pens For Rs160 A Person Loses 20%. How Many Ball Pens Should Be Sold At Rs.96 So As To Have A Profit Of 20% ?
Answer :
S.P of 90 ball pens = Rs 160
Loss= 20%
C.P = 10020×160
= Rs. 200
Now,
S.P of 90 ball pens = Rs. 96
Profit = 20%
C.P = 100120×96
= Rs .80
Rs .200 is the cost price of 90 ball pens.
Therefore, Rs.80 is the C.P of = 90 (80200) = 36 ball pens
Thus, 36 ball pens should be sold at Rs. 96 to earn a profit of 20%
Question 16. A Man Sells An Article At A Profit Of 25%. If He Had Bought It At A 20% Less And Sold It For Rs.36.75 Less, He Would Have Gained 30%. Find The Cost Price Of The Article ?
Answer :
Let the C.P be the article be Rs. x
Profit = 25%
Original S.P = x + 25100x
= Rs. 5×4
If he purchased it at 20% less,
C.P = x- 20100x
= Rs. 4×5
He sold the article at Rs. 36.75
So, the selling price = Rs. 5×4 – 36.75
Given, that he would have gained 30% selling at that price.
Therefore, gain% = S.P-C.P
= 5×4 -36.75 – 4×5
= 25x−16×20 -36.75
So, gain % = 9×20-36.75- 4×5(100)
= 18375x = 18375105
= x = 175
The cost price of the article is Rs. 175.
Question 17. If A Train, Travelling At A Speed Of 90 Kmph, Crosses A Pole In 5 Sec, Then The Length Of Train Is?
Answer :
D = 90 * 5/18 * 5 = 125 m
Question 18. A Dealer Bought Two Tables For Rs.3120. He Sold One Of Them At A Loss Of 15% And The Other At A Gain Of 36%. . Then, He Found That Each Table Was Sold For The Same Price. Find The Cost Price Of Each Table.
Answer :
Given that the selling price is same for both the tables.
Let the C.P of 1 table be x
Then the C.P of the other table be = Rs.3120-x
Loss on the first table = 15%
Therefore, S.P = 85×10
= 0.85x
Gain on the second table = 36%
136(3120-x)
Since both the tables have the same S.P
2.21x = 4243.20
= x= 1920
The cost price of the table is Rs.1920
The cost price of the other table is Rs.(3120-1920) = Rs.1200
Question 19. Mariam Bought Two Fans Rs.3605. She Sold One Of Them At A Profit Of 15% And The Other One At A Loss Of 9 %. If Mariam Obtained The Same Amount For Each Fan, Find The Cost Price Of The Each Of The Fans.
Answer :
It is given that the S.P is same for both of the fans.
Let the C.P of the first fan be Rs. x
Therefore, C.P of the second fan be Rs. (3605-x)
Profit on the first fan = 15%
Loss on the second fan = 6%
For the first fan, S.P = 115×100
= 23×20
For the second fan, S.P = 91×100
Since, S.P of both the fans is the same
= 23×20 = 3605 – 91×100
= x = 1592
C.P of the first fan = Rs. 1592
C.P of the second fan = Rs.(3605-1592)
= Rs. 2012.50
The cost prices of the both of the fans are Rs.1592 and Rs. 2012.50 respectively.
Question 20. Some Toffees Are Bought At A Rate Of 11 For Rs.10 And The Same Number At The Rate Of 9 For Rs.10. If The Whole Lot Is Sold At One Per Toffee, Find The Gain Or Loss Percent On The Whole Transaction.
Answer :
Let the total number of toffees bought be Rs. x
Let x2 at the rate of 11 are bought for Rs.10,
Total money spent on toffees = 200×198
= 100×99
It is given that x toffees are sold at Re.1 per toffee.
Therefore, the selling price of x toffees = Rs. x(1)
As C.P is more than S.P, it will be the loss.
Loss= C.P-S.P
= 100×99 – x
= x99
Loss% = 1%
The total loss on the whole transaction would be 1%
Question 21. A Tricycle Is Sold At A Gain Of 16%. Had It Been Sold For Rs.100 More, The Gain Would Have Been 20%. Find The C.p Of The Tricycle ?
Answer :
Let the S.P of the tricycle be Rs. x
Let the C.P of the tricycle be Rs. y
Gain % = 16%
Then we have,
= x= y+ 16y100
= x = y+ 0.16y
When S.P increases by Rs.100, we get
= x+ 100 = y + 20 y 100
Putting x = 1.6y
= 1.16y+100 = y+0.2y
= 1.16y +100 = 1.2y
= y = 2500
The C.P of the cycle is 2500
Thus, C.P of the tricycle is Rs. 2500.
Question 22. Shabana Bought 16 Dozens Ball Pens And Sold Them At A Loss Of To S.p Of 8 Ball Pens. Find:
(i) Her Loss Percent
(ii) P Of 1 Dozen Ball Pens, If She Purchased These 16 Dozens Ball Pens For Rs.576
Answer :
(i) Number of pens bought = 16(12) = 192
Let S.P of one pen be Rs. x
Therefore, S.P of 192 pens = 192x
C.P of 8 pens = Rs. 8x
It is given that S.P of 8 pens is equal to the loss on selling 192 pens.
Therefore, loss= Rs.8x
C.P of 192 pens = Rs 576
Loss = C.P –S.P
= 8x = 576 – 192×200
= 576 x = 576200
=x= 2.88
Therefore, loss= RS.23.04
Loss% = 4%
(ii) P of 1 pen = Rs.2.88
Therefore, S.P of 1 dozen pens = 12x = 12(2.88)
= Rs.34.56
Question 23. The Difference Between Two Selling Pieces Of A Shirt At A Profit Of 4 % And 5% Is Rs.6. Find:
(i) P Of The Shirt
(ii) The Two Selling Prices Of The Shirt
Answer :
Let the C.P of both the shirt be RS. X
For 1 shirt profit = 4%
Profit% = Rs. 0.04x
S.P = Rs.1.04x
For 2 shirt profit = 5%
Profit% = Rs. 0.05x
S.P = Rs.1.05x
It is given that the difference between their profits is Rs.6
So, 1.05x-1.04x = 6
= x = Rs.600
Thus, C.P = Rs.600
S.P of 1 shirt 1 = Rs.1.04x = Rs. 1.04(600)= Rs. 624
S.P of 1 shirt 2 = Rs.1.05x = Rs. 1.05(600)= Rs. 630
Question 24. Toshiba Bought 100 Hens For Rs.8000 And Sold 20 Of These At A Gain Of 5%. At What Gain Percent She Must Sell The Remaining Hens So As To Gain 20% On The Whole ?
Answer :
C.P of 100 hens = RS. 8000
Cost of one hen = 8000100
Rs. 80 C.P of 20 hens = Rs (80*20) = Rs. 1600
Gain = 5%
S.P = 105100×1600
= Rs. 1680
C.P of 80hens = Rs.(80*80) = Rs. 6400
Gain on 80 hens – C.P 80 hens
Gain on 100 hens = gain on 80 hens + gain on 20 hens
= 80+ S.P of 80 hens – 6400
S.P of 80 hens = Rs (1600+6400-80)
S.P of 80 hens = Rs. 7920
Gain on 80 hens = S.P of 80 hens – C.P of 80 hens
= Rs. (792-6400) = Rs. 1520
Gain % 80 hens = 15206400×100
= 23.75%
Therefore, Toshiba gained 23.75% on 80 hens.
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